The value of $\int\limits^{\frac{\pi}{2}}_{0}\frac{\sqrt{cot\, x}}{\sqrt{tan\, x}+\sqrt{cot\, x}}dx$ is :
Answer & explanation
Correct answer: option 4
$I=\int\limits^{\frac{\pi}{2}}_{0}\frac{\sqrt{\cot\, x}}{\sqrt{\tan\, x}+\sqrt{\cot\, x}}dx$ ....(1)
$I=\int\limits^{\frac{\pi}{2}}_{0}\frac{\sqrt{\cot(\frac{\pi}{2}-x)}}{\sqrt{\tan(\frac{\pi}{2}-x)}+\sqrt{\cot(\frac{\pi}{2}-x)}}dx$
$I=\int\limits^{\frac{\pi}{2}}_{0}\frac{\sqrt{\tan x}}{\sqrt{\cot x}+\sqrt{\tan x}}dx$ ...(2)
eq. (1) + eq. (2)
$2I=\int\limits^{\frac{\pi}{2}}_{0}1dx$
so $2I=\frac{\pi}{2}$
so $I=\frac{\pi}{4}$