A wire is looped in the form of a circle of diameter 70 cm. It is bent again into a square form. What will be the approximate length of the diagonal of the largest possible square? (Assume $π = 22/7$)

$55\sqrt{2}\, cm$

The correct answer is Option (4) → $55\sqrt{2}\, cm$

Step 1: Length of the wire (circumference of the circle)

Diameter = 70 cm

$\text{Circumference} = \pi d = \frac{22}{7} \times 70 = 220 \text{ cm}$

So, total wire length = 220 cm.

Step 2: Form a square with the same wire

Perimeter of square = 220 cm

$\text{Side of square} = \frac{220}{4} = 55 \text{ cm}$

Step 3: Diagonal of the square

Diagonal = $\text{side} \times \sqrt{2}$​

$= 55\sqrt{2} \text{ cm}$