Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

What is the simplified value of $cos^2 (90^o - θ) - [\frac{cos(90^o-θ)cosθ}{cotθ}]$?

Options:

4

2

0

1

Correct Answer:

0

Explanation:

$cos^2 (90^o - θ) - [\frac{cos(90^o-θ)cosθ}{cotθ}]$

{ using :-  cos (90º - θ)sin = θ }

= $sin^2  θ - [\frac{sinθcosθ}{cotθ}]$

= $sin^2  θ - sin^2  θ$ 

= 0