If $f(x)= 2x $ and $g(x)=\frac{x^2}{2}+1, $ then which of the following can be a discontinuous function ? |
$f(x)+g(x)$ $f(x)-g(x)$ $f(x).g(x)$ $\frac{g(x)}{f(x)}$ |
$\frac{g(x)}{f(x)}$ |
The correct answer is option (4) → $\frac{g(x)}{f(x)}$ f is not discontinuous g is not discontinuous $⇒fg,f+g,f-g$ can never be discontinuous but g/f is discontinuous at $f=0$, at $x=0$ since g/f is not defined at x = 0 |