Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Relations and Functions

Question:

If $f(x)= 2x $ and $g(x)=\frac{x^2}{2}+1, $ then which of the following can be a discontinuous function ?

Options:

$f(x)+g(x)$

$f(x)-g(x)$

$f(x).g(x)$

$\frac{g(x)}{f(x)}$

Correct Answer:

$\frac{g(x)}{f(x)}$

Explanation:

The correct answer is option (4) → $\frac{g(x)}{f(x)}$

f is not discontinuous g is not discontinuous

$⇒fg,f+g,f-g$ can never be discontinuous

but g/f is discontinuous 

at $f=0$, at $x=0$

since g/f is not defined at x = 0