Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

Match List-I with List-II. Here [x] denotes the greatest integer function

List-I

List-II

(A) $f(x) = [x]$

(I) is continuous everywhere but not differentiable at $x = −1$

(B) $f(x)=|x-1|$

(II) is continuous everywhere except at all integral values

(C) $f(x) = e^{|x|}$

(III) is continuous everywhere but not differentiable at $x = 1$

(D) $f(x) = |x+1|$

(IV) is continuous everywhere but not differentiable at $x = 0$

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Correct Answer:

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Explanation:

The correct answer is Option (2) → (A)-(II), (B)-(III), (C)-(IV), (D)-(I)

List-I

List-II

(A) $f(x) = [x]$

(II) is continuous everywhere except at all integral values

(B) $f(x)=|x-1|$

(III) is continuous everywhere but not differentiable at $x = 1$

(C) $f(x) = e^{|x|}$

(IV) is continuous everywhere but not differentiable at $x = 0$

(D) $f(x) = |x+1|$

(I) is continuous everywhere but not differentiable at $x = −1$

$\textbf{(A)}\; f(x)=\lfloor x \rfloor$

The greatest–integer function has jump discontinuities at every integer.

So it matches: “continuous everywhere except at all integral values.”

$A \to (II)$

$\textbf{(B)}\; f(x)=|x-1|$

Absolute value functions are continuous everywhere but not differentiable where the inside becomes zero → at $x=1$.

So it matches: “continuous everywhere but not differentiable at $x=1$.”

$B \to (III)$

$\textbf{(C)}\; f(x)=e^{|x|}$

Continuous everywhere, but $|x|$ is not differentiable at $x=0$, so $e^{|x|}$ is also not differentiable at $x=0$.

So it matches: “continuous everywhere but not differentiable at $x=0$.”

$C \to (IV)$

$\textbf{(D)}\; f(x)=|x+1|$

Non-differentiable where $x+1=0$ → at $x=-1$.

So it matches: “continuous everywhere but not differentiable at $x=-1$.”

$D \to (I)$

$\textbf{Final Answer: } A\to II,\; B\to III,\; C\to IV,\; D\to I$