Match List-I with List-II. Here [x] denotes the greatest integer function
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List-I |
List-II |
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(A) $f(x) = [x]$ |
(I) is continuous everywhere but not differentiable at $x = −1$ |
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(B) $f(x)=|x-1|$ |
(II) is continuous everywhere except at all integral values |
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(C) $f(x) = e^{|x|}$ |
(III) is continuous everywhere but not differentiable at $x = 1$ |
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(D) $f(x) = |x+1|$ |
(IV) is continuous everywhere but not differentiable at $x = 0$ |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
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List-I |
List-II |
|
(A) $f(x) = [x]$ |
(II) is continuous everywhere except at all integral values |
|
(B) $f(x)=|x-1|$ |
(III) is continuous everywhere but not differentiable at $x = 1$ |
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(C) $f(x) = e^{|x|}$ |
(IV) is continuous everywhere but not differentiable at $x = 0$ |
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(D) $f(x) = |x+1|$ |
(I) is continuous everywhere but not differentiable at $x = −1$ |
$\textbf{(A)}\; f(x)=\lfloor x \rfloor$
The greatest–integer function has jump discontinuities at every integer.
So it matches: “continuous everywhere except at all integral values.”
$A \to (II)$
$\textbf{(B)}\; f(x)=|x-1|$
Absolute value functions are continuous everywhere but not differentiable where the inside becomes zero → at $x=1$.
So it matches: “continuous everywhere but not differentiable at $x=1$.”
$B \to (III)$
$\textbf{(C)}\; f(x)=e^{|x|}$
Continuous everywhere, but $|x|$ is not differentiable at $x=0$, so $e^{|x|}$ is also not differentiable at $x=0$.
So it matches: “continuous everywhere but not differentiable at $x=0$.”
$C \to (IV)$
$\textbf{(D)}\; f(x)=|x+1|$
Non-differentiable where $x+1=0$ → at $x=-1$.
So it matches: “continuous everywhere but not differentiable at $x=-1$.”
$D \to (I)$
$\textbf{Final Answer: } A\to II,\; B\to III,\; C\to IV,\; D\to I$