Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

For $a \in[\pi, 2 \pi]$ and $n \in Z$, the critical points of $f(x)=\frac{1}{3} \sin a \tan ^3 x+(\sin a-1) \tan x+\sqrt{\frac{a-2}{8-a}}$, are 

Options:

$x=n \pi$

$x=2 n \pi$

$x=(2 n+1) \pi$

none of these

Correct Answer:

none of these

Explanation:

We have,

$f'(x)=\sin a+\tan ^2 x \sec ^2 x+(\sin a-1) \sec ^2 x$

$\Rightarrow f'(x)=\left(\sin a \tan ^2 x+\sin a-1\right) \sec ^2 x$

At critical points, we must have

$f'(x)=0$

$\Rightarrow \sin a \tan ^2 x+\sin a-1=0$            [∵  sec2x ≠ 0 for any x ∈ R]

$\Rightarrow \tan ^2 x=\frac{1-\sin a}{\sin a}$

Now,

$a \in[\pi, 2 \pi]$

$\Rightarrow \frac{1-\sin a}{\sin a}<0 $

$\Rightarrow \tan ^2 x=\frac{1-\sin a}{\sin a}$ does not have solution in R.

Hence, f(x) has no critical points.