Practicing Success
The equation $\sqrt{x+1}-\sqrt{x-1}= \sqrt{4x-1}$ has |
no solution one solution two solutions more than two solutions |
no solution |
We have, $\sqrt{x+1}-\sqrt{x-1}= \sqrt{4x-1}$ ...(i) $⇒(\sqrt{x+1}-\sqrt{x-1})^2=(\sqrt{4x-1})^2$ $⇒x+1+x-1-2\sqrt{x^2-1}=4x-1$ $⇒2x-2\sqrt{x^2-1}=4x-1$ $⇒-2\sqrt{x^2-1}=2x-1$ $⇒4(x^2-1)=(2x-1)^2$ $⇒4x^2-4=4x^2-4x+1⇒x=5/4$ But, $x=\frac{5}{4}$ does not satisfy equation (i). Hence, equation (i) has no solution. |