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If $\cot A=\frac{12}{5}$, then the value of sin A = ? |
$\frac{5}{13}$ $\frac{12}{13}$ $\frac{5}{12}$ $\frac{13}{12}$ |
$\frac{5}{13}$ |
Given :- cotA = \(\frac{12}{5}\) P2 + B2 = H2 52 + 122 = H2 H = 13 So , sinA = \(\frac{P}{H}\) = \(\frac{5}{13}\) |
