A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is :

0.5 mm 1.0 mm 0.01 mm 0.25 mm

0.5 mm

Least Count = \(\frac{Pitch}{No. of div}\) Least Count = 0.01 mm ; No. of div = 50 Pitch = 0.5 mm