If a student walks at a speed 30% more than the usual speed, he reaches 15 min earlier to his destination. How much time (in minutes) does he take to reach his destination normally?
Answer & explanation
Correct answer: option 2
Let initial speed = 100
New speed = 100 + 30 % of 100 = 130
As per the question,
The ratio of
speed 10 : 13
Time 13 : 10
( Time is inversely proportional ti Speed )
Difference 3R = 15 minutes
1R = \(\frac{15}{3}\) = 5 minutes
Usual Time taken = 13R = 13 × 5 = 65 minutes