If x4 + \(\frac{1}{x^4}\) = 49727, the positive value of ( x + \(\frac{1}{x}\) -15 ) is?
Answer & explanation
Correct answer: option 3
If x4 + \(\frac{1}{x^4}\) = a
then x2 + \(\frac{1}{x^2}\) = \(\sqrt {a + 2}\) = b
and x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\)
ATQ,
x4 + \(\frac{1}{x^4}\) = 49727
x2 + \(\frac{1}{x^2}\) = \(\sqrt {49727 + 2}\) = 223
So, ( x + \(\frac{1}{x}\) - 15 ) = ( \(\sqrt {223 + 2}\) - 15 ) = 0