In a school, class 1 had 10 football players, class 2 had 17 football players, class 3 had 8 football players and class 4 had 7 football players. If one single football player is to be selected for inter school football match then what is the probability that the player is either from class 2 or class 4? |
\(\frac{4}{21}\) \(\frac{7}{15}\) \(\frac{12}{21}\) \(\frac{17}{21}\) |
\(\frac{12}{21}\) |
Total number of players = 10 + 17 + 8 + 7= 42 The probability of selecting one class2 player = \(\frac{17}{42}\) The probability of selecting one class 4 player = \(\frac{7}{42}\) The reqd. probability =\(\frac{17}{42}\) + \(\frac{7}{42}\) = \(\frac{24}{42}\) = \(\frac{12}{21}\) Hence, option C is correct. |