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If cosecθ + cotθ = P find the value of \(\frac{P^2-1}{P^2+1}\) |
sinθ cosθ tanθ cotθ |
cosθ |
Let us assume a triangle.
Put in → cosecθ + cotθ = P \(\frac{Hyp.}{Perp}\)+\(\frac{Base}{Perp.}\)=P \(\frac{5}{3}\)+\(\frac{4}{3}\)=P P = 3 Now, \(\frac{P^2-1}{P^2+1}\)=\(\frac{9-1}{9+1}\)=\(\frac{8}{10}\) =\(\frac{4}{5}\) =\(\frac{B}{H}\)= cosθ |
