The radius of curvature of the path of a charged particle in a uniform magnetic field is directly proportional to the
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → momentum of the particle
The radius of curvature of a charged particle moving perpendicular to a uniform magnetic field is given by:
$r = \frac{mv}{qB}$
Here, $m$ is mass, $v$ is velocity, $q$ is charge, and $B$ is magnetic flux density.
Momentum of the particle: $p = mv$
Therefore, $r = \frac{p}{qB}$
Hence, the radius of curvature is directly proportional to the momentum of the particle.
Answer: momentum of the particle