If sec A = 9/4 then what is the value of cot A ?

We are given that,

sec A = \(\frac{9}{4}\)

{ using , sec A = \(\frac{H}{B}\) }

By using pythagoras theorem ,

P² + B² = H²

P² + 4² = 9²

P² = 81 - 16 = 65

P = \(\sqrt { 65}\)

Now,

cotA

= \(\frac{B}{P}\)

= \(\frac{4}{√65}\)