A is twice as good a workman as B and together they finish a piece of work in 22 days. In how many days will A alone finish the same work?
Answer & explanation
Correct answer: option 4
Given,
A is twice as good a workman as B, therefore,
A : B = 2 : 1 (Efficiency)
They complete the work in 22 days together = (2 + 1) x 22 = 3 x 22 = 66 units, ..(Efficiency × Days = Total work)
⇒ Time required by A to complete the work alone = \(\frac{66}{2}\) = 33 days, ..(\(\frac{Work}{Efficiency}\) = Time)