A is twice as good a workman as B and together they finish a piece of work in 22 days. In how many days will  A alone finish the same work?

33 days

Given,

A is twice as good a workman as B, therefore,

A : B = 2 : 1 (Efficiency)

They complete the work in 22 days together = (2 + 1) x 22 = 3 x 22 = 66 units,   ..(Efficiency × Days = Total work)

⇒ Time required by A to complete the work alone = \(\frac{66}{2}\) = 33 days,   ..(\(\frac{Work}{Efficiency}\) = Time)