Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Organic: Haloalkanes and Haloarenes

Question:

How many monohaloalkane isomers can be formed on the free radical bromination of (CH3)2CHCH2CH3?

Options:

2

3

4

5

Correct Answer:

4

Explanation:

There are four different types of hydrogen atoms that can be replaced to give the following four isomers; (CH3)2CHCH2CH2Br, (CH3)2CHCH(Br)CH3, (CH3)2C(Br)CH2CH3 and CH3CH(CH2Br)CH2CH3.