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In the above problem, the energy density associated with the electric field will be: |
$\frac{1}{2} CV^2$ $\frac{1}{2} \frac{q^2}{C}$ $\frac{1}{2} \frac{\varepsilon^2}{E}$ $\frac{1}{2} \varepsilon_0 E^2$ |
$\frac{1}{2} \varepsilon_0 E^2$ |
Learn this. $u = \frac{1}{2} \varepsilon_0 E^2$ |
