If $\theta \in [0, \pi ]$ is the angle between any two non zero vectors $\vec{a}$ and $\vec{b}$, such that $|\vec{a}.\vec{b}|=|\vec{a}×\vec{b}|$ then $\theta = $ |
$\frac{\pi}{2}$ $\frac{\pi}{4}$ 0 $\pi $ |
$\frac{\pi}{4}$ |
The correct answer is Option (2) → $\frac{\pi}{4}$ $|\vec{a}.\vec{b}|=|\vec{a}×\vec{b}|$ $=|\vec{a}||\vec{b}|\cos θ=|\vec{a}||\vec{b}|\sin θ$ $\cos θ=\sin θ⇒θ=\frac{\pi}{4}$ |