If 8cotθ = 6, then the value of $\frac{sinθ+cosθ}{sinθ-cosθ}$ is :

12 7 2 5

7

8cotθ = 6 cotθ =  \(\frac{6}{8}\) B = 6 & P = 8 P2 + B2 = H2 82 + 62 = H2 H = 10 sinθ + cosθ = \(\frac{8}{10}\) + \(\frac{6}{10}\)  = \(\frac{14}{10}\)  sinθ - cosθ = \(\frac{8}{10}\) - \(\frac{6}{10}\) = \(\frac{2}{10}\) Now , \(\frac{sinθ + cosθ}{sinθ -cosθ}\) =\(\frac{14}{2}\) = 7