If $ (a+ 1)^2 + 9A+ 2)^2 = 16 $ then wha

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If $ (a+ 1)^2 + 9A+ 2)^2 = 16 $ then what is the value of 40 + 12 a + 4a² ?

Options:

Correct Answer:

Explanation:

If $ (a+ 1)^2 + (A+ 2)^2 = 16 $

what is the value of 40 + 12 a + 4a² ?

(a+ 1)^2 + (A+ 2)^2 = 16 $

a² + 1 + 2a + a² + 4 + 4a = 16

2a² + 6a + 5 = 16

2a² + 6a = 11

Multiply the above equation by 2

4a² + 12a = 22

Now put this in 40 + 12 a + 4a²

40 + 22 = 62