If $ (a+ 1)^2 + 9A+ 2)^2 = 16 $ then what is the value of 40 + 12 a + 4a2 ?
Answer & explanation
Correct answer: option 2
If $ (a+ 1)^2 + (A+ 2)^2 = 16 $
what is the value of 40 + 12 a + 4a2 ?
(a+ 1)^2 + (A+ 2)^2 = 16 $
a2 + 1 + 2a + a2 + 4 + 4a = 16
2a2 + 6a + 5 = 16
2a2 + 6a = 11
Multiply the above equation by 2
4a2 + 12a = 22
Now put this in 40 + 12 a + 4a2
40 + 22 = 62