Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

The function $f(x)=\cot^{-1}\sqrt{(x+3)x}+\cos^{-1}(\sqrt{x^2+3x+1})$ is defined on the set S, where S is equal to

Options:

(−3, 0)

[0, 3]

[−3, 0]

{−3, 0}

Correct Answer:

{−3, 0}

Explanation:

For the two components to be meaningful $(x +3)x ≥ 0$ and $0≤x^2+3x+1≤1$

Hence $(x + 3)x = 0 ⇒ x = 0, − 3$