In the given figure, O is the centre of the circle. If ∠BAO = 30° and ∠BCO = 50°, then ∠AOC is equal to:
Answer & explanation
Correct answer: option 1
We have,
∠BAO = 30°
∠BCO = 50°,
then ∠AOC= 2 × ( ∠BAO + ∠BCO )
= 2 × ( 30 + 50 ) = 160°
In the given figure, O is the centre of the circle. If ∠BAO = 30° and ∠BCO = 50°, then ∠AOC is equal to:
Correct answer: option 1
We have,
∠BAO = 30°
∠BCO = 50°,
then ∠AOC= 2 × ( ∠BAO + ∠BCO )
= 2 × ( 30 + 50 ) = 160°