A potential difference of 6 V is applied across a conductor of length 12 cm. If the mobility of electrons is $5.6 × 10^{-6} m^2/Vs$, their drift velocity will be:

$2.8 × 10^{-4} m/s$

The correct answer is Option (3) → $2.8 × 10^{-4} m/s$

Given:

Potential difference: $V = 6 \, \text{V}$

Length of conductor: $L = 12 \, \text{cm} = 0.12 \, \text{m}$

Electron mobility: $\mu = 5.6 \times 10^{-6} \, \text{m}^2/\text{Vs}$

Electric field: $E = \frac{V}{L} = \frac{6}{0.12} = 50 \, \text{V/m}$

Drift velocity: $v_d = \mu E = (5.6 \times 10^{-6}) \cdot 50 = 2.8 \times 10^{-4} \, \text{m/s}$

Answer: $v_d = 2.8 \times 10^{-4} \, \text{m/s}$