CUET Preparation Today
If x - \(\frac{1}{x}\) = 7\(\sqrt{2}\) then find the value of ( x + \(\frac{1}{x}\) ) |
10 12 13 8 |
10 |
⇒ If x - \(\frac{1}{x}\) = a then x + \(\frac{1}{x}\) = \(\sqrt {a^2 + 4}\) Here, x - \(\frac{1}{x}\) = 4\(\sqrt{6}\), then ⇒ x + \(\frac{1}{x}\) = \(\sqrt {(4\sqrt{6})^2 + 4}\) = 10 |
