If x - \(\frac{1}{x}\) = 7\(\sqrt{2}\)
then find the value of ( x + \(\frac{1}{x}\) )
Answer & explanation
Correct answer: option 1
⇒ If x - \(\frac{1}{x}\) = a then x + \(\frac{1}{x}\) = \(\sqrt {a^2 + 4}\)
Here,
x - \(\frac{1}{x}\) = 4\(\sqrt{6}\), then
⇒ x + \(\frac{1}{x}\) = \(\sqrt {(4\sqrt{6})^2 + 4}\) = 10