Calculate the mass of an atom of silver.

\(1.793 × 10^{–22}g\)

The correct answer is option 1. \(1.793 × 10^{–22}g\).

\(\text{1 mole of Ag atoms = 108g} \text{ = }6.022\text{ × }10^{23}\)

\(6.022\text{ × }10^{23}\text{ atoms of silver have mass = 108g}\)

∴ \(\text{Mass of one atom of silver (Ag) =}\frac{108}{6.022\text{ × }10^{23}}\text{ = }1.793 × 10^{–22}g\)