What is the set of values of x satisfying $x+1= 32 (mod\, 7)$ ?
Answer & explanation
Correct answer: option 4
The correct answer is option (4) : $x=...., 10, 17, 24, 31, 38, 45, 52, ............$
$x+1=32(mod\, 7)$
$x+1-32$ is divisible by 7
$x-31 $ is a multiple of 7
$x-31=7\lambda , λ∈I$
$x=31+7\lambda $
Putting $\lambda = ....., -3, -2, -1, 0 , 1, 2, 3, ......$ we get
$x=...., 10, 17, 24, 31, 38, 45, 52, ............$