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What is the set of values of x satisfying $x+1= 32 (mod\, 7)$ ? |
$x=...., 8, 16, 24, 32, 38, 40, 48, ............$ $x=...., 9, 13, 17, 21, 25, 29, 33, ............$ $x=...., 11, 16, 21, 26, 31, 36, 41, ............$ $x=...., 10, 17, 24, 31, 38, 45, 52, ............$ |
$x=...., 10, 17, 24, 31, 38, 45, 52, ............$ |
The correct answer is option (4) : $x=...., 10, 17, 24, 31, 38, 45, 52, ............$ $x+1=32(mod\, 7)$ $x+1-32$ is divisible by 7 $x-31 $ is a multiple of 7 $x-31=7\lambda , λ∈I$ $x=31+7\lambda $ Putting $\lambda = ....., -3, -2, -1, 0 , 1, 2, 3, ......$ we get $x=...., 10, 17, 24, 31, 38, 45, 52, ............$ |
