Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If sin Y = x, then what will be the value of cos 2Y (where 0 ≤ Y ≤ 90°) ?

Options:

$(\sqrt{2}-1) x$

$\sqrt{2}x$

$1-2x$

$1-2x^2$

Correct Answer:

$1-2x^2$

Explanation:

Given :-

sinY = x

We know ,

cos2A = 1 - 2 sin2A

cos2Y = 1 - 2 sin2Y

= 1 - 2x2