A die is thrown. Find the probability of getting: (A) A number greater then 6 and (B) A number less than 3.

$0,\frac{1}{3}$ $1,\frac{1}{2}$ $\frac{1}{2},0$ $\frac{1}{2},\frac{1}{3}$

$0,\frac{1}{3}$

The correct answer is Option (1) → $0,\frac{1}{3}$