If x - \(\frac{1}{x}\) = 4\(\sqrt{2}\) then find the value of x3 + \(\frac{1}{x^3}\)

110 200 198 202

198

⇒ If x - \(\frac{1}{x}\) = a then x + \(\frac{1}{x}\) = \(\sqrt {a^2 + 4}\) and If x + \(\frac{1}{x}\) = a then ⇒ x3 + \(\frac{1}{x^3}\) = a3 - 3a ATQ, x - \(\frac{1}{x}\) = 4\(\sqrt{2}\), then  ⇒ x + \(\frac{1}{x}\) = \(\sqrt {(4\sqrt{2})^2 + 4}\) = 6 ⇒ x3 + \(\frac{1}{x^3}\) = 63 - 3 × 6 = 198