The cost of tiling the floor of a rectangular room is ₹9100 at ₹65 per m2. The ratio of the length and breadth of the floor is 7 : 5. The perimeter (in m) of the floor of the room is: |
36 24 48 28.8 |
48 |
We know that, Area of rectangle = Length × Breadth Perimeter of rectangle = 2(l + b) We have, The cost of tiling the floor of a rectangular room = Rs. 9100 at Rs. 65 m2 The ratio of the length and breadth of rectangle = 7 : 5 Let the length and breadth of a rectangle be 7a and 5a respectively. According to the question , Area of the floor of a rectangular room = = \(\frac{9100}{65}\) m2 = 140 m2 Area of rectangle floor= (7a × 5a) = 35a2 = 140 = a2 = 4 = a = 2 Perimeter of rectangle roomed floor = 2(7 × 2 + 5 × 2) = 2(14 + 10) = 2 × 24 = 48 m |