Match List-I with List-II

Choose the correct answer from the options given below:

(A)-(III), (B)-(I), (C)-(II), (D)-(IV)

The correct answer is Option (4) → (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

(A) Glucose: * Glucose is a non-electrolyte (covalent compound).

• It does not dissociate into ions in water.

• Therefore, its van't Hoff factor is $i = 1$.

• Matching: (A)-(III)

(B) $K_2SO_4$ (Potassium Sulfate): * This salt dissociates as follows: $K_2SO_4 \rightarrow 2K^+ + SO_4^{2-}$.

• The total number of ions produced is $2 + 1 = 3$.

• Therefore, its van't Hoff factor is $i = 3$.

• Matching: (B)-(I)

(C) $Ca_3(PO_4)_2$ (Calcium Phosphate): * This salt dissociates as follows: $Ca_3(PO_4)_2 \rightarrow 3Ca^{2+} + 2PO_4^{3-}$.

• The total number of ions produced is $3 + 2 = 5$.

• Therefore, its van't Hoff factor is $i = 5$.

• Matching: (C)-(II)

(D) $K_3[Fe(CN)_6]$ (Potassium Ferricyanide): * This is a coordination compound that dissociates as follows: $K_3[Fe(CN)_6] \rightarrow 3K^+ + [Fe(CN)_6]^{3-}$.

• The coordination sphere ($[Fe(CN)_6]^{3-}$) remains intact as a single ion.

• The total number of ions produced is $3 + 1 = 4$.

• Therefore, its van't Hoff factor is $i = 4$.

• Matching: (D)-(IV)