Match List-I with List-II
|
List-I Molecule |
List-II van't Hoff Factor |
|
(A) Glucose |
(I) 3 |
|
(B) $K_2SO_4$ |
(II) 5 |
|
(C) $Ca_3(PO_4)_2$ |
(III) 1 |
|
(D) $K_3[Fe(CN)_6]$ |
(IV) 4 |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
|
List-I Molecule |
List-II van't Hoff Factor |
|
(A) Glucose |
(III) 1 |
|
(B) $K_2SO_4$ |
(I) 3 |
|
(C) $Ca_3(PO_4)_2$ |
(II) 5 |
|
(D) $K_3[Fe(CN)_6]$ |
(IV) 4 |
(A) Glucose: * Glucose is a non-electrolyte (covalent compound).
- It does not dissociate into ions in water.
- Therefore, its van't Hoff factor is $i = 1$.
- Matching: (A)-(III)
(B) $K_2SO_4$ (Potassium Sulfate): * This salt dissociates as follows: $K_2SO_4 \rightarrow 2K^+ + SO_4^{2-}$.
- The total number of ions produced is $2 + 1 = 3$.
- Therefore, its van't Hoff factor is $i = 3$.
- Matching: (B)-(I)
(C) $Ca_3(PO_4)_2$ (Calcium Phosphate): * This salt dissociates as follows: $Ca_3(PO_4)_2 \rightarrow 3Ca^{2+} + 2PO_4^{3-}$.
- The total number of ions produced is $3 + 2 = 5$.
- Therefore, its van't Hoff factor is $i = 5$.
- Matching: (C)-(II)
(D) $K_3[Fe(CN)_6]$ (Potassium Ferricyanide): * This is a coordination compound that dissociates as follows: $K_3[Fe(CN)_6] \rightarrow 3K^+ + [Fe(CN)_6]^{3-}$.
- The coordination sphere ($[Fe(CN)_6]^{3-}$) remains intact as a single ion.
- The total number of ions produced is $3 + 1 = 4$.
- Therefore, its van't Hoff factor is $i = 4$.
- Matching: (D)-(IV)