Practicing Success
Fifteen coupons are numbered 1, 2, 3, …. 15. Seven coupons are selected at random one at a time with replacement. The probability that the largest number appearing on the selected coupon is 9, is |
$\left(\frac{9}{16}\right)^6$ $\left(\frac{8}{15}\right)^7$ $\left(\frac{3}{5}\right)^7$ none of these |
none of these |
Total ways = 157 For favorable ways, we must 7 coupons numbered from 1 to 9 so that '9' is selected atleast once. Thus total number of favorable ways are, 97 - 87 ⇒ Required probability = $\frac{9^7-8^7}{15^7}$ |