If ΔABC is isosceles triangle with AB = AC and ∠ABC is 65°, ∠BCA and ∠BAC are, respectively:
Answer & explanation
Correct answer: option 1
AB = AC (ΔABC is an isosceles triangle)
∠ABC = 65°
We know that,
If AB = AC then,
∠ ABC = ∠ACB = 65°
So, ∠BCA = ∠ACB = 65°
∠ABC + ∠ BAC + ∠ACB = 180°
∠BAC = 180° - 130°
∠BAC = 50°