The value of $[\sin x]+[1 + \sin x] + [2+ \sin x]$ in $x∈(π, 3π/2]$ can be ([-] is the greatest integer function) can be.

0 1 2 3

0

We have, $[\sin x]+[1 + \sin x] + [2 + \sin x]$ $= [\sin x]+1+[\sin x] + 2 + [\sin x]$ $= 3+3 [\sin x]$ $=3+ 3× (-1)=0$ $[∵ [\sin x] = -1\, for\, x ∈ (π, 3π/2]$