The frequency of a photon of energy 2.3 eV emitted due to transition of electron from higher energy level to lower energy level is
Answer & explanation
Correct answer: option 1
The correct answer is option (1) : $555\times 10^{12}Hz$
$hf=2.3\times 1.6\times 10^{-19}⇒f=\frac{2.3\times 1.6\times 10^{-19}}{6.62\times 10^{-34}}$
$⇒f=0.55589\times 10^{15}Hz ≈555\times 10^{12} Hz$