The frequency of a photon of energy 2.3 eV emitted due to transition of electron from higher energy level to lower energy level is

$555\times 10^{12}Hz$ $320\times 10^{10}Hz$ $555\times 10^{10}Hz$ $555\times 10^{12}Hz$

$555\times 10^{12}Hz$

The correct answer is option (1) : $555\times 10^{12}Hz$ $hf=2.3\times 1.6\times 10^{-19}⇒f=\frac{2.3\times 1.6\times 10^{-19}}{6.62\times 10^{-34}}$ $⇒f=0.55589\times 10^{15}Hz ≈555\times 10^{12} Hz$