The area of a rectangle is 20 cm2. Its length is 5 cm. Find the diagonal of rectangle.
Answer & explanation
Correct answer: option 2
Area of rectangle = length (l) × breadth (b)
20 = 5 × b
b = 4 cm
Diagonal of rectangle = \(\sqrt {l^2 + b^2}\)
= \(\sqrt {5^2 + 4^2}\)
= \(\sqrt {25 + 16}\)
= \(\sqrt {41}\)