The area of a rectangle is 20 cm2. Its length is 5 cm. Find the diagonal of rectangle.

$\sqrt{38}$cm $\sqrt{41}$cm $\sqrt{35}$cm $\sqrt{21}$cm

$\sqrt{41}$cm

Area of rectangle = length (l) × breadth (b) 20 = 5  × b b = 4 cm Diagonal of rectangle = \(\sqrt {l^2 + b^2}\)                                = \(\sqrt {5^2 + 4^2}\)                                = \(\sqrt {25 + 16}\)                                = \(\sqrt {41}\)