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The correct 4f sub-shell electronic configuration of $Yb^{2+}$ ion is |
$4f^{14}$ $4f^{13}$ $4f^{12}$ $4f^7$ |
$4f^{14}$ |
The correct answer is Option (1) → $4f^{14}$ Ytterbium (Yb) has atomic number 70.
$[Xe]\,4f^{14} 6s^2$
$Yb^{2+} : [Xe]\,4f^{14}$ |
