The following pie chart represents the percentage-wise distribution of 300 students of class X in a school in six different sections A, B, C, D, E and F.
The given table shows the number of boys of class X in six different sections A, B, C, D, E and F.
| Section | A | B | C | D | E | F |
| No. of Boys | 36 | 26 | 34 | 28 | ....... | 20 |
The total number of boys in sections A, B and D together is what percentage more than the total number of girls in sections A. B and D together?
Answer & explanation
Correct answer: option 4
Number of boys in section A , B & D = 36 + 26 + 28 = 90
Number of girls in A , B & D = Total number of students in A , B & D - Number of boys in section A , B & D
Total number of students in all sections = 300
Total number of students in A , B & D = \(\frac{20+18+17 }{100}\) ×300
= \(\frac{ 55 }{100}\) ×300
= 165
Total number of girls = 165 - 90 = 75
Percentage of more boys in A , B & D than girls in A, B & D
= \(\frac{ 90-75 }{75}\) × 100
= \(\frac{ 15 }{75}\) × 100
= 20%