If $Δ=\begin{vmatrix}1&a&bc\\1&b&ca\\1&c&ab\end{vmatrix}$, then

Δ = (a - b) (b - c) (c - a)

Here $Δ=\begin{vmatrix}1&a&bc\\1&b&ca\\1&c&ab\end{vmatrix}=\frac{1}{abc}\begin{vmatrix}a&a^2&abc\\b&b^2&abc\\c&c^2&abc\end{vmatrix}$

$=\begin{vmatrix}1&a&a^2\\1&b&b^2\\1&c&c^2\end{vmatrix}= (a - b) (b – c) (c – a)$

Hence (A) is the correct answer.