Practicing Success
Practicing Success
CUET Preparation Today
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a b c d |
c |
$ \nu = Rc (\frac{1}{2^2} - \frac{1}{4^2}) = \frac{3Rc}{16} = \frac{3 \times 10^7 \times 3\times 10^8}{16} = \frac{9}{16} \times 10^{15}$ |
