The following table gives the length, diameter and applied potential difference of four copper wires, A, B, C and D, across their ends. Arrange the wires in correct order of the increasing electric field.
|
|
Length |
Diameter |
Potential difference |
|
(A) Wire A |
I |
3d |
V |
|
(B) Wire B |
2I |
d |
V |
|
(C) Wire C |
3I |
2d |
2V |
|
(D) Wire D |
3I |
2d |
V |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → (D), (B), (C), (A)
$E = \frac{V}{l}$
$\text{Wire A: } E_A = \frac{V}{l}$
$\text{Wire B: } E_B = \frac{V}{2l}$
$\text{Wire C: } E_C = \frac{2V}{3l}$
$\text{Wire D: } E_D = \frac{V}{3l}$
$\text{Compare: } \frac{V}{3l} < \frac{V}{2l} < \frac{2V}{3l} < \frac{V}{l}$
$E_D < E_B < E_C < E_A$
The correct order is D < B < C < A.