The following table gives the length, diameter and applied potential difference of four copper wires, A, B, C and D, across their ends. Arrange the wires in correct order of the increasing electric field.

Choose the correct answer from the options given below:

(D), (B), (C), (A)

The correct answer is Option (4) → (D), (B), (C), (A)

$E = \frac{V}{l}$

$\text{Wire A: } E_A = \frac{V}{l}$

$\text{Wire B: } E_B = \frac{V}{2l}$

$\text{Wire C: } E_C = \frac{2V}{3l}$

$\text{Wire D: } E_D = \frac{V}{3l}$

$\text{Compare: } \frac{V}{3l} < \frac{V}{2l} < \frac{2V}{3l} < \frac{V}{l}$

$E_D < E_B < E_C < E_A$

The correct order is D < B < C < A.