What is the area (in sq cm) of an equilateral triangle of side 14 cm?

49√3 98√3 (49/2) √3 (49/4) √3

49√3

Area of eq. = \(\frac{ \sqrt{3}}{4}\)a2                  = \(\frac{ \sqrt{3}}{4}\) × 14 × 14                  = 49\(\sqrt{3}\) cm2