If a, b, c, d, e & f are six consecutive odd numbers, their average is :

4(a + b) \(\frac{abcdef} {5}\) (a + 5) 5(a + b + c + d + e + f)

(a + 5)

Let the numbers a,b,c,d,e are = 3 , 5 , 7 , 9 , 11 , 13 Average = \(\frac{Sum \; of \; numbers}{Total \; number \; of \; numbers}\)               =  \(\frac{ 3 + 5 + 7 + 9 + 11 + 13}{6}\) = 8 Now verify from options = Choose option (a + 5) Here a = 3 a + 5 = 3 + 5 = 8 verified Ans. = (a + 5)