An unbiased die is rolled. If the random variable $\mathrm{X}$ is defined as,

$X= \begin{cases}1 & \text { if the outcome is a number less than or equal to } 3 \\ 0 & \text { if the outcome is a number greater than } 3\end{cases}$

Then the probability distribution of X is :

$x= \begin{cases}1 & \text { outcome } \leq 3 \\ 0 & \text { outcome }>3\end{cases}$

Total outcomes of a die = 6

for x = 1 (outcomes $\leq$ 3) → no of favourable cases = 3

(since 1, 2, 3 are less than or equal to 3)

for x = 0 (outcomes > 3) → no of favourable cases = 3

(since 4, 5, 6 are greater than or equal to 3)

probability distribution