How many of the following lanthanoid ions are paramagnetic?
La3+, Ce3+, Ce4+, Nd3+, Eu2+, Gd3+, Yb2+, Lu3+
(Atomic numbers: La = 57, Ce = 58, Nd = 60, Eu = 63, Gd = 64, Yb = 70, Lu = 71)
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 4
An ion is paramagnetic when it has unpaired electrons. Lanthanoid ions lose the 6s electrons first, then the 5d electron if there is one, and then 4f electrons. An ion with an empty (f0) or completely filled (f14) 4f subshell has no unpaired electron and is diamagnetic; every other lanthanoid ion is paramagnetic.
Paramagnetic:
Ce3+ (Ce is [Xe]4f15d16s2; Ce3+ is 4f1, one unpaired electron)
Nd3+ (Nd is [Xe]4f46s2; Nd3+ is 4f3, three unpaired electrons)
Eu2+ (Eu is [Xe]4f76s2; Eu2+ is 4f7, seven unpaired electrons)
Gd3+ (Gd is [Xe]4f75d16s2; Gd3+ is 4f7, seven unpaired electrons)
Diamagnetic (not counted):
La3+ — La is [Xe]5d16s2, so La3+ is 4f0.
Ce4+ — 4f0.
Yb2+ — Yb is [Xe]4f146s2, so Yb2+ is 4f14.
Lu3+ — Lu is [Xe]4f145d16s2, so Lu3+ is 4f14.
Paramagnetic ions: Ce3+, Nd3+, Eu2+ and Gd3+ = 4.
NCERT (2026-27 edition):
4.5.4 General Characteristics – “…The lanthanoid ions other than the f0 type (La3+ and Ce4+) and the f14 type (Yb2+ and Lu3+) are all paramagnetic.”