What will be the resistance of an aluminium wire of length 1.2 m and cross sectional area $2.6 mm^2$. The resistivity of aluminium is $2.6 \times 10^{-8} \Omega m$ |
$1.2 \times 10^{-8} \Omega$ $1.2 \times 10^{-5} \Omega$ $1.2 \times 10^{-2} \Omega$ $2.2 \times 10^{-2} \Omega$ |
$1.2 \times 10^{-2} \Omega$ |
The correct answer is Option (3) → $1.2 \times 10^{-2} \Omega$ Resistance of an wire (R) - $R=ρ\frac{L}{A}$ where, Resistivity $(ρ) = 2.6 × 10^{-8}Ωm$ Length $(l)=1.2m$ Sectional Area $(A) = 2.6mm^2=2.6× 10^{-6}m^2$ $R=\frac{2.6 × 10^{-8} × 1.2}{2.6 × 10^{-6}}$ $=1.2 \times 10^{-2} \Omega$ |