Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

In a series RLC circuit at resonance

(A) Impedance is maximum
(B) $X_C = X_L$
(C) $Z= R$
(D) $ω =\frac{1}{\sqrt{LC}}$

Choose the correct answer from the options given below:

Options:

(A), (B) and (D) only

(A), (B) and (C) only

(A), (B), (C) and (D)

(B), (C) and (D) only

Correct Answer:

(B), (C) and (D) only

Explanation:

The correct answer is Option (4) → (B), (C) and (D) only

  • (A) Impedance is maximum (Incorrect): The impedance ($Z$) of a series RLC circuit is given by: $Z = \sqrt{R^2 + (X_L - X_C)^2}$

    At resonance, since $X_L = X_C$, the term $(X_L - X_C)$ becomes zero. This results in the minimum possible impedance, which is simply equal to the resistance ($R$). Consequently, the current in the circuit is at its maximum.

  • (B) $X_C = X_L$ (Correct): This is the fundamental condition for resonance. The two reactances oppose each other perfectly.

  • (C) $Z = R$ (Correct): As shown in the formula above, when $X_L = X_C$, the impedance $Z$ simplifies to $\sqrt{R^2}$, which is $R$. The circuit behaves as a purely resistive circuit.

  • (D) $\omega = \frac{1}{\sqrt{LC}}$ (Correct): Resonance occurs at angular frequency: $\omega = \frac{1}{\sqrt{LC}}$m.