A student multiplied a number with $\frac{3}{4}$ instead of $\frac{4}{3}$. What is the error percentage ?

43.75%

Let the number is = 12 ( LCM of 4 , 3 )

Number get by multiplying with wrong number =  \(\frac{3}{4}\) × 12 = 9

Actual number to get =  \(\frac{4}{3}\) × 12 = 16

Error percentage =  \(\frac{16-7}{16}\) × 100

=  \(\frac{9}{16}\) × 100

= 43.75%