CUET Preparation Today
If \(\sqrt {15}\) sinθ = 3, find the value of tanθ . |
\(\frac{5}{2}\) 1 \(\frac{3}{2}\) \(\frac{3}{\sqrt {6}}\) |
\(\frac{3}{\sqrt {6}}\) |
\(\sqrt {15}\) sinθ = 3 sinθ = \(\frac{3}{\sqrt {15}}\) (where 3 → P and \(\sqrt {15}\) → H) B = \(\sqrt {(\sqrt {15})^2 - (3)^2}\) B = \(\sqrt {6}\) Put all the values → tanθ = \(\frac{P}{B}\) = \(\frac{3}{\sqrt {6}}\) |
